Chasing Cats and Dogs: Solving for Time and Distance

  • Thread starter Thread starter ILC grade 11
  • Start date Start date
  • Tags Tags
    Physics
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 2K views
ILC grade 11
Messages
5
Reaction score
0

Homework Statement


A cat running at a constant speed of 5.0 m/s runs by a dog sitting on a driveway. The dog gives the cat a chase 5 seconds later and accelarates at 0.5 m/s^2
a) how long does it take the dog to catch upwith the cat? b) how far from the driveway is the dog when it catches the cat

I know I have to make a data table but I don't know what to plug in and what equations to use please help
 
Physics news on Phys.org
I don't know about a data table. I would tackle this using the equations of motion.

Have you studied equations of motion under constant acceleration?

[tex]x(t) = x_0 + v_0 t + \frac{1}{2} a\cdot t^2[/tex]
where x(t) is the position at time t given initial position, initial velocity and constant acceleration.

The cat is not accelerating so its position will be simply:
[tex]x(t) = x_0 + vt[/tex]

Write the equation for the dogs and cats position as a function of time. You may want to set t=0 to be when the dog starts running (figure out how far ahead the cat is at this time and that is the cat's initial position).

The dog catches the cat when they both have the same position.
 
oh ok thanks a lot i understand it now