How Do You Graph Kinetic Energy Against Time and Distance?

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Homework Help Overview

The discussion revolves around the calculation and graphical representation of kinetic energy in a physics problem involving a mass acted upon by a horizontal force. The subject area includes concepts of kinetic energy, acceleration, and graphing in the context of motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate kinetic energy and plot graphs against time and distance. They express confusion about whether the kinetic energy values should be the same for both graphs and seek clarification on how to begin plotting.

Discussion Status

Participants have engaged in clarifying the nature of the graphs, noting that while the kinetic energy value at a specific time is the same, the plots represent different relationships. Guidance has been provided regarding the expected shapes of the graphs, with some participants confirming the original poster's understanding of the graphical representations.

Contextual Notes

There is mention of the need to post in the homework section and use the appropriate template, indicating adherence to forum rules. The original poster has expressed concerns about the accuracy of their calculations and the representation of their graphs.

james123
<Moderator's note: Moved from a technical forum and thus no template.>

A horizontal force of 80 N acts on a mass of 6 kg resting on a horizontal surface. The mass is initially at rest and covers a distance of 5 m in 0.92 s under the action of the force. Assuming there are no energy losses due to air resistance and therefore that the acceleration is constant:
  1. (a) Calculate the total energy expended in the acceleration.

    (b) Plot a graph of the kinetic energy of the mass against time.

    (c) Plot a graph of the kinetic energy of the mass against distance. Work done so far:

    1. (a) 80 x 5= 400J

    1 (b) a= 2d/t^2
    a=(2x5)/0.92^2
    a=11.8147448
    a=11.81 m/s^-2

    v=at
    v=11.8147448 x 0.932
    v=10.86956522

    KE=1/2m(at)2
    KE=0.5 x 6(10.86956522)^2
    KE=354.4423442 J

    1 (c) KE=1/2m(2ad)
    KE=0.5 x 6(2 x 11.8147448 x 5
    KE=354.442344 JMy main questions are, should I expect the same answers for both questions? seems a little odd to me.
    Also, I'm completely stumped on the graphs, how to start them, how to plot them etc.

    Any help is greatly appreciated!
 
Last edited by a moderator:
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james123 said:
should I expect the same answers for both questions? seems a little odd to me.
Why ? There is only one kinetic energy at t = 0.92 s, which is what you calculated in b) and c). What the exercise asks is a plot of KE vs t in b) and vs d in c). So far you have two points (t=0 and t = 0.92 s) for the first and two points (d=0 and d=5 m) for part c).

Please post in the homework section and use the template

Oh, and if the exercise given data are in two digits, don't report in 10 digits (calculating in that many digits is just fine though, with todays equipment :smile:).
 
Hi, thanks for replying.

I have now posted in the homework section.

I think I was just suspicious about getting two of the same answers, I assumed I was doing something wrong.

After thinking about it, it now makes sense, just got to figure out these graphs!
 
My first graph for 1(b) has ended up looking like this, is this along the right lines??
untitled-jpg.jpg
 
Does it look like a graph of
james123 said:
KE=1/2m(at)2 ?
And: does it show
james123 said:
KE=354 J
at t = 0.92 s ?
 
Sorry, the graph I posted was generic and isn't mine, just used it as an example to show the general shape of what I ended up with.

That said, I've re-done the graphs and think I have it. Please ignore the values as again these aren't my graphs.

For question 1 (b) I have this graph where KE grows exponentially.
upload_2017-8-10_13-58-44.jpeg

And for 1(c) I have needed up with a straight line graph

untitled-jpg-jpg.jpg


Still trying to figure out how to upload my own pictures from a MacBook! Are these the shaped of graph I should expect??

Thanks for chipping in so far, I really appreciate it
 
james123 said:
Are these the shaped of graph I should expect?
Yes. a parabola for KE=1/2m(at)2 and a straight line for KE=1/2m(at)2
 

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