Check answer please simple diff eq'n problem involving eulers method

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SUMMARY

The discussion centers on solving the differential equation dy/dt = -4t + 2 with the initial condition y(0) = 1 using Euler's method. The solution derived is y(t) = -2t² + 2t + 1, and upon evaluating at t = 1, the result is confirmed as y(1) = 1. The calculations are validated, confirming the correctness of the solution.

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Homework Statement



dy/dt = -4t+2
y(0) = 1
find y(1)=?

Homework Equations





The Attempt at a Solution



so first i solve the diff equation:
dy/dt = -4t + 2
dy=(-4t+2)dt
∫dy=∫(-4t+2)dt
y(t) = -2t^(2)+2t+C
y(0)=1
1=-2(0)^(2)+2(0)+C_1
1=C_1

y(t) = -2t^(2)+2t+1

now i solve for y(1)..

y(1)=-2(1)^(2)+2(1)+1
y(1)=1


is this correct??
 
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