- #1

MaryBarnes

- 27

- 0

## Homework Statement

a 0.25 kg piece of ice at -30°C is warmed by an electric heater and the following graph of temperature is produced.

-use the information on the graph to determine the power output of the heater

the graph shows that the ice went from -30degC to -10 degC in 150s

## Homework Equations

Q=mcΔt

p=w/Δt

## The Attempt at a Solution

Q=mcΔt

=(0.25)(3.3*10

^{5})((-30)-(-20))

=82500*(-20)

1.65*10

^{6}

should this be negative?

p=w/Δt

=1.65*10

^{6}/150

=11000