- #1
- 1
- 0
Homework Statement
If a man has an average useful power output of 41.4 W, what minimum time would it take him to lift fifty 15.0-kg boxes to a height of 1.88 m?
Homework Equations
1/2mv(final)^2 mgy(final) = 1/2mv(initial)^2 mgy(initial)
P=W/Δt
P=Fv
The Attempt at a Solution
Dont even know where to start