Work, Force, Energy and power question about moving car.

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving work, force, energy, and power related to a car's motion. The original poster presents a scenario where a car with a specified power output is traveling at a constant speed, seeking to determine the force exerted by the engine.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between power, force, and velocity, with some questioning the implications of constant speed on force application. There is discussion about the relevance of power equations and their application to the problem.

Discussion Status

Participants have engaged in clarifying the concepts of power and force, with some suggesting that the relationship P = F*v could be applied to derive the force. There is an acknowledgment of the original poster's confusion regarding energy changes and force application.

Contextual Notes

There is a noted assumption that the car is moving at a constant speed, which raises questions about the net force acting on it. The original poster expresses uncertainty about the implications of this condition on the force exerted by the engine.

Ethan_Tab
Messages
57
Reaction score
2

Homework Statement


A car has a power output of 45kW and travels at a constant speed of 30m/s. What force is the engine applying on the car?

Homework Equations


F=m*a
W=ΔKE+ΔGPE
KE=½mv^2
GPE=mgh
W=F*d
P=ΔE/ΔT
gh_1+½v_1^2=gh_2+½v_2^2

The Attempt at a Solution


I really have no clue. Since there is no change in energy (ΔE) in terms of kinetic or gravitational potential energy, I don't know what to do.

Any help is much appreciated.
 
Physics news on Phys.org
Does F*v (Force*Velocity) sound familiar to you ?
[Edit: In case not, power is change of energy over change in time, so P = ΔW/Δt = Δ(F*x)/Δt = F*Δx/Δt = F*v]
 
Last edited:
Noctisdark said:
Does F*v (Force*Velocity) sound familiar to you ?

Yes, but usually only in the context of force of friction where

P=Ff*d/t and as such P=Ff*v.

Am I missing something about this question?
 
You're right, but not only for friction,
In general, P = dW/dt so you can work it out here :)
 
Noctisdark said:
You're right, but not only for friction,
In general, P = dW/dt so you can work it out here :)

Hmm.. so with that I get,

45kW=ΔF*d/Δt---since ΔF*d or ΔKE is 0, does that mean the engine is not applying any force on the car?
 
If the engine is applying some force on the car, it would be accelerating and but it's moving at a constant speed (and have a mass) so it has kenetic energy in fact, but it's not the purpose of the exercice I guess, it would be better to consider, in this case that P = F*v and take a force out of that :)
 
  • Like
Likes   Reactions: Ethan_Tab
Aha! I understand. Thanks for the help mate :)
 
  • Like
Likes   Reactions: Noctisdark
Welcome ^^ :)
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
Replies
29
Views
3K
Replies
5
Views
9K