(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A ceramic pot of mass 0.5 kg will break if it strikes the floor with an impact force equal

to, or greater than, 20 N. The collision lasts for 0.05 s. Find the minimum vertical height

from which, if dropped from rest, the pot will break upon impact with the floor (you

may ignore air resistance).

2. Relevant equations

Impulse=FΔt=P_{final}-P_{inital}

Fd=ΔKinetic energy

PE=mgh

KE=1/2mv^{2}

3. The attempt at a solution

At a height h, the object has KE=0 and PE=mgh=0.5gh

At impact, the object has KE=1/2mv^{2}=0.25v^{2}and PE=0

FΔt=P_{f}-P_{i}

However P_{i}=0 as the velocity is 0.

equation 1: 20*0.05=P_{f}=mv=0.5v

to find v:

1/2mv^{2}=mgh

rearrange to give v=√2gh

back into equation 1:

1=0.5^{2}*2gh

h=1/0.5_{2}*2*9.81

h=0.2m

Is this correct? That doesn't seem big enough in order for the pot to break (thinking in real world terms)

**Physics Forums - The Fusion of Science and Community**

# Checking a question involving impact/impulse forces

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Checking a question involving impact/impulse forces

Loading...

**Physics Forums - The Fusion of Science and Community**