Checking if sets are subspaces of ##\mathbb{R}^{3}##

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Homework Help Overview

The discussion revolves around determining whether a specific set, defined by the condition \( W = \left \{ \begin{bmatrix} x\\ y\\ z \end{bmatrix}: x \leq y \leq z \right \} \), is a subspace of \( \mathbb{R}^{3} \). Participants are exploring the properties that define a subspace in the context of linear algebra.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the necessary properties of a subspace, including the need to contain the zero vector, and to be closed under scalar multiplication and addition. Questions arise about how to demonstrate these properties using arbitrary members of the set.

Discussion Status

The conversation is focused on clarifying the properties that need to be verified for the set to be considered a subspace. Some participants are seeking guidance on how to approach the proof, while others are reiterating the conditions that must be satisfied.

Contextual Notes

There is an emphasis on the need to explicitly verify the three properties of a subspace, but the specific steps or methods for doing so have not been detailed in the discussion.

yango_17
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Homework Statement


Is the set ##W## a subspace of ##\mathbb{R}^{3}##?
##W=\left \{ \begin{bmatrix}
x\\
y\\
z
\end{bmatrix}:x\leq y\leq z \right \}##

Homework Equations

The Attempt at a Solution


I believe the set is indeed a subspace of ##\mathbb{R}^{3}##, since it looks like it will satisfy the three properties of a subspace. I'm wondering as to how one would go about explicitly proving this. Any help would be appreciated. Thanks.
 
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yango_17 said:

Homework Statement


Is the set ##W## a subspace of ##\mathbb{R}^{3}##?
##W=\left \{ \begin{bmatrix}
x\\
y\\
z
\end{bmatrix}:x\leq y\leq z \right \}##

Homework Equations

The Attempt at a Solution


I believe the set is indeed a subspace of ##\mathbb{R}^{3}##, since it looks like it will satisfy the three properties of a subspace. I'm wondering as to how one would go about explicitly proving this. Any help would be appreciated. Thanks.
What are the three properties you need to verify? You didn't list them in the 2nd section or anywhere else.

Generally, you take one or two arbitrary members of your set and show that the set is closed under addition and scalar multiplication.
 
So, the properties would be that the set needs to contain the zero vector, needs to be closed under scalar multiplication, and needs to be closed under addition. When you say take arbitrary members of the set to test the last two properties, what exactly do you mean?
 
yango_17 said:
So, the properties would be that the set needs to contain the zero vector, needs to be closed under scalar multiplication, and needs to be closed under addition. When you say take arbitrary members of the set to test the last two properties, what exactly do you mean?
Let, say, ##\vec{u}## and ##\vec{v}## be elements of W, with ##\vec{u} = <u_1, u_2, u_3>## and ##\vec{v} = <v_1, v_2, v_3>##.
What condition do these vectors need to satisfy in order to belong to set W? You are given this condition.

Is 0 an element of W?
If ##\vec{u}## and ##\vec{v}## are arbitrary members of W, is ##\vec{u} + \vec{v}## also in W?
If ##\vec{u}## is an arbitrary member of W, and k is an arbitrary scalar, is ##k\vec{u}## also in W?

If the answers to these questions are all "yes", then the set is a subspace of ##\mathbb{R}^3##.
 

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