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find the volume of the solid bounded above by x^2+y^2+z^2=9, below by z=0 and on the sides by the cylinder x^2+y^2=4.

Now rho comes out to be 3. At the very top of the solid, phi is 0 so z=3.

So limits of z are 0 (lower limit) and 3 (upper limit).

As far as the limits of x and y are I found their lower and upper limits to be 0 and 2 respectively.

When we do the triple integal ∫∫∫dxdydz (while pluggung the limits) I got 12 (units of volume) . Is this the correct way and answer for this question?