Checking my answer/approach - specific gravity of a mixture

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The specific gravity of a mixture containing 40% ethyl alcohol and 60% water is calculated to be 0.916. The approach involved assuming a 100 mL mixture, determining the mass of water and ethyl alcohol based on their densities, and then calculating the total mass and density of the mixture. The density of ethyl alcohol was found to be 0.79 g/mL, leading to a total mass of 91.6 g for the mixture. The final specific gravity is derived by dividing the density of the mixture by the density of water. The calculation is confirmed to be accurate for volume percentages.
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Homework Statement


What is the specific gravity of a mixture 40% ethyl alcohol and 60% water? The specific gravity of ethyl alcohol is 0.79.

Homework Equations


The Attempt at a Solution


He showed us a way to do it for another type of problem but I approached it a bit differently and I wanted to make sure my answer was logical/correct before submitting it. So what I did was this:

Assume 100 mL of mixture. Then you have 40 mL alcohol, 60 mL water.
Density of water = 1 = mass/60 mL; mass of water therefore = 60 g
0.79 = density of alcohol/density of water (1), so density of alcohol = 0.79
I set up a cross multiplication:

0.79 g/1 mL = x g/40 mL
I got 31.6 g of ethyl alcohol.

So the total mass of the mixture is 91.6 g.

Thus the density of the mixture is 91.6 g/100 mL = 0.916

Thus specific gravity of the mixture = 0.916/1 = 0.916.

Does this seem accurate?
 
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Yes, that's right, if the 60% and 40% were by volume.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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