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Misplaced Homework Thread

The vapour density of N204 at certain temperature is 30. Calculate the percentage of dissociation of N204 at this temperature. N2O4(g)⇌2NO2(g)?

I am unable to understand the concept behind vapour density of the mixture.

Currently, I understand that

2 x vapour density=molar mass.

Vapour density =

mass of n molecules of gas ÷ mass of n molecules of hydrogen.

Vapour density

= molar mass of gas ÷ molar mass of H₂.

I am unable to apply the above formula because a mixture does not have molar mass.

And I am also not able to understand that if

2 x vapour density=molar mass

then in the question, molar mass of N204 at the certain temperature given would be 60 instead of 92.

The correct answer is 53.33%

I am unable to understand the concept behind vapour density of the mixture.

Currently, I understand that

2 x vapour density=molar mass.

Vapour density =

mass of n molecules of gas ÷ mass of n molecules of hydrogen.

Vapour density

= molar mass of gas ÷ molar mass of H₂.

I am unable to apply the above formula because a mixture does not have molar mass.

And I am also not able to understand that if

2 x vapour density=molar mass

then in the question, molar mass of N204 at the certain temperature given would be 60 instead of 92.

The correct answer is 53.33%