What is the final temperature of the mixture?

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Homework Help Overview

The problem involves mixing two quantities of water at different temperatures: 10 g of water at 0 degrees Celsius and 100 g of water at 20 degrees Celsius. The goal is to determine the final temperature of the mixture, considering the specific heat capacity of water and the latent heat of fusion.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the approach of equating heat gained and lost by the two water masses, with one participant noting a potential sign error in the calculations. Others highlight that the final temperature must logically fall between the initial temperatures of the two water samples.

Discussion Status

The discussion is ongoing, with participants providing insights into the setup of the problem and questioning the assumptions made regarding heat transfer. Some guidance has been offered regarding the need to consider the signs of heat transfer, but there is no explicit consensus on the correct approach yet.

Contextual Notes

One participant has noted that latent heat of fusion was ignored, as the water from the ice is already melted. There is also a reminder to keep discussions focused on the current problem without introducing unrelated questions.

FlyDoc
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Homework Statement



10 g of water from a water ice mixture (0 degrees C) is added to100 g of water at 20 degrees celsius. what is the final temperature of the mixture? C of water =1 kcal/kg*C Latent Heat of Fusion of water=79.7 kcal/kg

Homework Equations



Q=mC(Tf-Ti)
Q=mL

The Attempt at a Solution



I ignored Latent heat of fusion since the 0 degree water form the water-ice is already melted. I just set mC(Tf-Ti) of water from water-ice equal to mC(Tf-Ti) of water. I got 22 degrees. Book answer is 18.2. Where am I going wrong?
 
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Probably a sign error: One part heats up, one part cools down, so you have to swap the sign on one side. Otherwise, you add the same amount of heat to both parts.
 


If you mix water at 0C with some other water at 20C, then the final temp of the mixture must be between 0C and 20C.
 


FlyDoc said:

The Attempt at a Solution



I ignored Latent heat of fusion since the 0 degree water form the water-ice is already melted. I just set mC(Tf-Ti) of water from water-ice equal to mC(Tf-Ti) of water. I got 22 degrees. Book answer is 18.2. Where am I going wrong?

mC(Tf-Ti) for water and for ice are of equal magnitude but of opposite signs, as the warm water loses heat while the cold water gains.
The sum of the mC(Tf-Ti) terms is zero.

ehild
 


when 260g of metal shots at 200^C are mixed in an ice-water bath (m of ice is 50g, m of water is 90g) which is in a 105 g copper container, the final temperature of the mixture was 10^C. assuming no heat energy was lost from the system, what is the value of the specific heat capacity of the metal
 


Please start a new thread for a new question. In addition, please show your attempts to solve the problem.
 

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