Chemical Kinetics Qn: Why is D Not a Possible Answer?

Click For Summary
SUMMARY

The discussion centers on the chemical kinetics question regarding why option D is not a valid answer in the context of increasing temperature and its effects on reaction rates and pressure. The correct answer is C, as doubling the initial volume of SO2 effectively doubles the initial moles of SO2, leading to an increase in the moles of SO3 produced and subsequently higher pressure, which is not reflected in the graph. Additionally, while increasing temperature does enhance the rate of reaction, it alters the equilibrium composition, affecting the pressure of sulfur trioxide (SO3) based on whether the reaction is endothermic or exothermic.

PREREQUISITES
  • Understanding of chemical kinetics and reaction rates
  • Knowledge of equilibrium composition in chemical reactions
  • Familiarity with the concepts of endothermic and exothermic reactions
  • Ability to interpret graphical data related to chemical reactions
NEXT STEPS
  • Study the principles of chemical equilibrium and Le Chatelier's principle
  • Learn about the effects of temperature on reaction rates and equilibrium
  • Explore the differences between endothermic and exothermic reactions
  • Investigate graphical representations of reaction kinetics and equilibrium shifts
USEFUL FOR

Chemistry students, educators, and professionals in the field of chemical engineering or research who are looking to deepen their understanding of reaction kinetics and equilibrium dynamics.

nicholaschean
Messages
19
Reaction score
0
FCpTz.jpg


The correct answer states its C which i understand why since doubling the intiial volume of SO2 is equivilent to doubling the intial moles of SO2 hence the moles of SO3 produced will also increase and hence pressure exerted shld be higher than before which is not reflected by the graph.

However, why is D not a possible answer? When temperature increases, the reactant particles will gain energy and cause rate of reaction to increase which is reflected by the graph here. But the SO3 particles produce will also be more active compared to lower temperature in experiment 1, hence shouldn't it exert a higher pressure than experiment 1? which in this case is not shown on the graph.
 
Chemistry news on Phys.org
nicholaschean said:
FCpTz.jpg


The correct answer states its C which i understand why since doubling the intiial volume of SO2 is equivilent to doubling the intial moles of SO2 hence the moles of SO3 produced will also increase and hence pressure exerted shld be higher than before which is not reflected by the graph.

However, why is D not a possible answer? When temperature increases, the reactant particles will gain energy and cause rate of reaction to increase which is reflected by the graph here. But the SO3 particles produce will also be more active compared to lower temperature in experiment 1, hence shouldn't it exert a higher pressure than experiment 1? which in this case is not shown on the graph.

Increasing the temperature will change the equilibrium composition, and your sulfur trioxide pressure would have a different horizontal asymptote.

The asymptote will move up or down depending on whether the reaction is endothermic or exothermic.

Note that increasing temperature WILL increase the rate of reaction.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
8
Views
3K
  • · Replies 11 ·
Replies
11
Views
1K
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 10 ·
Replies
10
Views
4K