Chemistry - Change of freezing point

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SUMMARY

The discussion centers on calculating the freezing point of mercury under pressure, given its enthalpy of fusion (2.292 kJ/mol) and normal freezing point (234.3 K). The change in molar volume upon melting is +0.517 cm³/mol, and the density of mercury is 13.6 g/cm³. The suggested approach involves using the Clausius-Clapeyron relation to account for the effects of pressure on the freezing point of mercury in a 10.0 m column.

PREREQUISITES
  • Understanding of thermodynamic principles, specifically phase transitions.
  • Familiarity with the Clausius-Clapeyron equation.
  • Knowledge of enthalpy and its role in phase changes.
  • Basic concepts of pressure, temperature, and volume relationships in fluids.
NEXT STEPS
  • Study the Clausius-Clapeyron equation and its applications in phase transitions.
  • Learn about the properties of mercury, including its phase diagram and enthalpy of fusion.
  • Explore calculations involving pressure effects on freezing and boiling points of substances.
  • Investigate the relationship between density, height, and pressure in fluid columns.
USEFUL FOR

Chemistry students, thermodynamics enthusiasts, and anyone involved in studying phase transitions and their effects on freezing points under varying pressures.

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Homework Statement


The enthalpy of fusion of mercury is 2.292kJ/mol and its normal freezing point s 234.3K with a change in molar volume of +0.517cm^3 /mol on melting. At what temperature will the bottom of a column of mercury (density 13.6 g/cm^3) of height 10.0m be expected to freeze.



Homework Equations





The Attempt at a Solution


I'm really not sure how to go about this. I though I could work out the Potential energy, using P = mgh. Then maybe take this off the enthalpy of fusion. I don't want the answer, but some though-provoking advice would be much appreciated. Thanks!
 
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Phase transition, pressure, temperature, volume change and enthalpy - that cries for a specific equation (relation). It is most often used for boiling points, but it works for every transition.
 
Clausius-Clapeyron?
 
That's what I would try.
 

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