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winterwind
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Homework Statement
The enthalpy of fusion of mercury is 2.292 kJ/mol, and its normal freezing point is 234.3 K with a change in molar volume of +0.517 cm/mol on melting. At what temperature will the bottom of a column of mercury (density 13.6 g /cm3) of height 10.0 m be expected to freeze?
Homework Equations
p = [tex]\rho[/tex]gh
p = p* + [([tex]\Delta[/tex]fusH)[tex]/[/tex](T*[tex]\Delta[/tex]fusV)]/(T - T*)
The Attempt at a Solution
I calculated the pressure in the column of mercury using the first equation provided above. I then solved the second equation for T, plugged in the given values, with p*= 101 kPa and T* = 234.3 K (the normal pressure and boiling point).
I get an answer of 234.2 K, which doesn't make sense, since when you raise the pressure, shouldn't you get a higher temperature freezing/melting point? I would expect it changes more than 0.1 K anyways.
Am I using the correct equation?
Thanks!
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