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Chemistry problem, calculate percent ionization

  1. Feb 13, 2007 #1
    acetic acid is a weak acid that ionizes in solution as follows
    CH3COOH--->CH3COO- + H+

    if the freezing point of a .106 m CH3COOH solution is -.203 celcius, calculate the percent of the acid that has undergone ionization.

    here's what i did, i took .203 celcius=i)1.86 celcius/m (.106m)

    then i put .203/1.86(.106)=.103 which is i
    then i took .103/2*100=5.15%
    2 is the actual number formula units dissolved in the solution,

    so did i do it right, it's a weak acid right, but i'm not sure if the percent is right
  2. jcsd
  3. Feb 13, 2007 #2
    so anyone know how to figure this out
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