Chemistry question,constant of equilibrum?

  • Thread starter Thread starter Questions999
  • Start date Start date
  • Tags Tags
    Chemistry
Click For Summary
SUMMARY

The discussion focuses on calculating the total pressure of a chlorine gas equilibrium reaction at 3000 K, specifically for the reaction Cl2 ⇌ 2Cl. The equilibrium constant for this reaction is given as 0.570 atm. The user correctly applies the ideal gas law, using the formula p = n/V * R * T, where the molar mass of Cl is 34 g/mol. The user also notes the importance of maintaining precision in calculations, particularly in the final answer.

PREREQUISITES
  • Understanding of chemical equilibrium and equilibrium constants
  • Familiarity with the ideal gas law (p = n/V * R * T)
  • Knowledge of molar mass calculations
  • Basic algebra for solving equilibrium problems
NEXT STEPS
  • Study the concept of chemical equilibrium and its applications in reactions
  • Learn about the ideal gas law and its implications in thermodynamics
  • Explore advanced equilibrium calculations involving multiple species
  • Investigate the effects of temperature on equilibrium constants
USEFUL FOR

Chemistry students, chemical engineers, and professionals involved in thermodynamic calculations and chemical reaction analysis will benefit from this discussion.

Questions999
Messages
151
Reaction score
0
In 3000 K the constant of disintegration in the equilibrum of the reaction Cl2-> ( <-) 2Cl is 0.570 atm.In the equilibrum the reaction weighs 3 miligrams and is contained in a dish with volume 60 mL and the temperature is 3000 K.Find the total pressure.

So I used p=n/V*R*T where n=m/M when M is the molar mass =34 ( since the molar mass of Cl is 17, 17*2=34). And R=0.08
Then I did Cl 2Cl
First (p1 I found) 0

Change -x 2x
Equilibrum p1-x 2x

Here by the constant of equilibrum I tried to find x ...am i right?
 
Physics news on Phys.org
Not easy to follow what you wrote, but I don't see anything that would in an obvious way suggest you are wrong.

For sure you should not round down all these numbers so heavily, as the answer you will get will be off. Round down only the final answer.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 11 ·
Replies
11
Views
5K
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
8K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
10K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 4 ·
Replies
4
Views
11K