Child sliding down a frictionless slide

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SUMMARY

A child sliding down a frictionless slide will lose contact with the slide at a height h, which can be determined using the principles of energy conservation and centripetal motion. The derived formula states that h equals 2H/3 when the radius R is greater than or equal to 2H/3; otherwise, h equals R. The relationship between potential energy (mgH), kinetic energy (1/2 mv^2), and centripetal force (F=mv^2/r) is crucial for solving this problem. This analysis confirms the importance of understanding energy conservation and centripetal dynamics in physics.

PREREQUISITES
  • Understanding of potential and kinetic energy concepts
  • Familiarity with centripetal force equations
  • Knowledge of energy conservation principles
  • Basic algebra for solving equations
NEXT STEPS
  • Study the conservation of mechanical energy in physics
  • Learn about centripetal acceleration and its applications
  • Explore the dynamics of motion on curved paths
  • Investigate real-world applications of frictionless surfaces in physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of energy conservation and centripetal force in action.

jfreimer
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Homework Statement



A child starts from rest and slides down a frictionless slide. In terms of R and H,
at what height h will he lose contact with the section of radius R?

(child starts at the top with height H, at the bottom the slide flattens out and then forms a quarter circle to the ground with radius R)


Homework Equations





The Attempt at a Solution


I tried figuring it out using potential energy and kinetic energy since that is the chapter. I think it has something to do with mgH=mgh+1/2mv^2 and then solving v^2 for some value using centripetal motion but I wasn't sure how to set that step up.
 
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I had you attempt at a solution in mind as well. Equating Potential Energies and solving. Now, what is the equation for Centripetal Force?

[tex]F=\frac{mv^2}{r}[/tex]

Just work from there.
 
My attempt for a solution has given the answer h=2H/3 if R >=2H/3 , else h=R
Is it possible?
 

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