What is the angular acceleration of each wheel?

Click For Summary

Homework Help Overview

The problem involves a bicycle coming to a stop, with specific details about the angular velocity and displacement of the wheels during braking. The subject area includes angular motion and kinematics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the relationship between angular displacement and angular velocity, questioning the use of kinematic equations. There are attempts to manipulate formulas to find time and angular acceleration, with some participants expressing uncertainty about their calculations.

Discussion Status

Some participants have offered guidance on unit conversion between revolutions and radians, which appears to have helped clarify the calculations. Multiple interpretations of the problem are being explored, and there is no explicit consensus on the correct answers yet.

Contextual Notes

Participants are navigating the constraints of converting angular displacement from revolutions to radians and ensuring the correct application of kinematic equations. There is an ongoing discussion about the accuracy of their calculations and the assumptions being made.

rcmango
Messages
232
Reaction score
0

Homework Statement



A person is riding a bicycle, and its wheels have an angular velocity of +20.0 rad/s.

Then, the brakes are applied and the bike is brought to a uniform stop.

During braking, the angular displacement of each wheel is +10.0 revolutions.

(a) How much time does it take for the bike to come to rest?
in seconds

(b) What is the angular acceleration of each wheel?
in rad/s2

Homework Equations





The Attempt at a Solution



what is the symbol of a revolution. Can i use a kinematic equation for this.
 
Physics news on Phys.org
hm..angular displacement.\theta is related to angular velocity,\omega
by the equation:


\omega=\frac{\theta}{t}




where t is time
 
okay, so if i manipulate the formula to look like t = theta / w

then the time is .5 seconds, however, that is not correct?
 
a)for the first one use kinematics formula

x=\frac{(v_0+v_f)}{2}t

so we have
\theta=\frac{(\omega_0+\omega_f)}{2}t

b)\alpha=\frac{d\omega}{dt}=\frac{d\omega}{dt}\frac{d\theta}{d\theta}

\alpha d\theta=\omega d\omega

\alpha\theta=\frac{\omega^2}{2}
 
for the first one, 1 second isn't the anwer and I'm not sure why

i used 10 rev = (+20 - 0)/2 t

so 1 second??

also, for the second one

20^2 = 400

so 400/2

=200
and that is not correct either.

i'm not sure what i did wrong.
 
Last edited:
You're mixing revolutions with radians, you'll have to convert units to one or the other.
 
thanks, that fixed it, i didn't realize that 1 revolution is actually convert to 2 * pi radians

i got the answers: 6.3 seconds and -3.17 rad/s^2
 

Similar threads

Replies
7
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
19
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 20 ·
Replies
20
Views
3K