Magnetic field at a point due to current carrying wires

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SUMMARY

The discussion focuses on calculating the magnetic field at a point due to six segments of current-carrying wires using the formula B = (μ * i * φ) / (2 * π * R). The user successfully calculates the magnetic field for segments 2 and 3, obtaining a value of 0.0000035969 Tesla for segment 3, and notes that segment 4's field is double that of segment 3. The user seeks assistance in determining the contributions from segments 5 and 6, concluding that segments 1 and 6 do not contribute to the magnetic field at point A due to their configuration.

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Homework Statement



magneticfield.jpg


Homework Equations



B =( \mu * i * \phi ) / (2 * \pi * R)



The Attempt at a Solution



i wanted to add one more equation, but I am having difficulty in writing them. whatever!

As you can see from the question there are 6 segments of current carrying wires.

For segment 1 which is labeled in the picture above, B = 0, because the wire goes directly towards the point.

For segment 2 (the semi-circular arc), the magnetic field is calculated using the equation above. where \phi = \pi.

For segment 3, i calculated the B-field and i think its correct...it is 0.0000035969 Tesla.

For segment 4, the B-field is twice as much of segment 3.

the problem now is that i don't know how to calculate the field due to segments 5 and 6. I am not sure if they produce any magnetic field that act on point A.

so please if anyone could help as soon as possible.

thanks in advance
 
Last edited:
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I think it is safe to assume here that segments 1 and 6 are insulated and touching each other in which case you have current running in a closed loop consisting of a semicircle and a rectangular piece. The contribution from 5 is tha same as the contribution from 3 and the contribution frm 6 is zero.
 

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