Circuit analysis is this correct?

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SUMMARY

The discussion focuses on solving a circuit analysis problem using Kirchhoff's Voltage Law (KVL) and Kirchhoff's Current Law (KCL). The initial attempt incorrectly applied KVL, leading to an erroneous value for I2. After correcting the approach by recognizing the current source's influence on R3, the final calculation determined that I2 equals 3 A. The correct relationships established were I1 = 3I2 and I1 - I2 = 2I2.

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Homework Statement



We have the the circuit in the figure.
gCUraSq.jpg


Homework Equations


I have to find I2.
KVL,KCL.


The Attempt at a Solution


I apply KVL in the "left " part of the circuit and I have -42 V+ 2I1 +8I2=0 .(I 1 is the current through 2 Ohm).I apply KCL in the nod between R1 R3 and R2 and I have (Current through R3)=I1-I2. I apply KVL in the right part of the circuit and I have -8I2+4(I1-I2) +2I2=0. I form a system with -42 V+ 2I1 +8I2=0 and -8I2+4(I1-I2) +2I2=0 and here I find that I1=(10/4)*I2.I replace this in 2I1+8I2=42 and I have I2=3.2 A.Is this correct?
 
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No, J = 2I2 is a current source. So your KVL expression for the second loop is not correct; you cannot say offhand what the potential drop across that current source will be.

Note that this current source tells you something about the current flowing through R3...
 
Oh,that current is 2I.So now I have I1-I2=2I2. Then I1=3I2.I replace this in 2I1+8I2=42. Now I have 14I2=42.Now I2=3 A.Thanks :)
 

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