Circuit Components-Potential differencd across LDR (photoresistor)

Click For Summary
SUMMARY

The discussion focuses on calculating the potential difference across a Light Dependent Resistor (LDR) in a potential divider circuit involving a variable resistor. The circuit operates with a variable resistor set at 2.4kΩ and an LDR resistance of 3.6kΩ in darkness. The final calculated potential difference across the LDR is 3.6V. The resistance of the buzzer is considered negligible due to its extremely high value, which is why it is not included in the calculations.

PREREQUISITES
  • Understanding of potential divider circuits
  • Knowledge of Ohm's Law (V=RI)
  • Familiarity with series circuit principles
  • Basic concepts of resistance in electrical components
NEXT STEPS
  • Study the principles of potential divider circuits in detail
  • Learn about the characteristics and applications of Light Dependent Resistors (LDRs)
  • Explore the impact of component resistance on circuit behavior
  • Investigate the role of buzzers and their resistance in electronic circuits
USEFUL FOR

Students studying electronics, hobbyists working with circuits, and educators teaching about potential dividers and LDR applications.

wei1006
Messages
6
Reaction score
0

Homework Statement


The following figure shows a potential divider circuit made up of a LDR and a variable resistor R. It is used to activate a buzzer circuit which sounds only at 2.6V and above. The resistance of the variable resistor varies from 100ohm to 10kohm while the resistance of the LDR varies from 110ohm to 3.6kohm.
1432254436688.jpg


Switch is now closed. The variable Resistor R is set at 2.4kohm and tje potential divider circuit is placed in a room with no light. Calculate the potential difference across the LDR.

Homework Equations


V=RI
Total p.d across a series circuit= add up the p.d of all components.
Total resistance across a series circuit= add up resistance of all components
Current is the same throughout the whole series circuit.

The Attempt at a Solution


I thought of ratio and proportion but I could not find the total resistance as I do not have the Total current... The final answer of this question is 3.6V.

Please help, thank you![/B]
 
Physics news on Phys.org
Hey, I got the answer...though I 'm wondering why the resistance of the buzzer is not taken into account. Since there is no light, the resistance of the LDR would be at max value, 3.6kΩ. So just add it with resistance of variable resistor to get and find the ratio of the resistance of LDR to total. Multiply that answer with 6V.
 
Oh I see. Thank you! The resistance of the buzzer is extremely large(stated in part 2 of the question) and I guess that is related to why it is not regarded...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 45 ·
2
Replies
45
Views
4K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 9 ·
Replies
9
Views
10K
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
3K
Replies
9
Views
4K