Circuit Problem. Potential Difference

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Homework Help Overview

The discussion revolves around calculating the potential difference Vab between two points in a circuit, involving resistances and electromotive forces (emfs). Participants explore the implications of reversing the polarity of one of the batteries while keeping the other constant.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Kirchhoff's rules and the calculation of total resistance in the circuit. There are questions about the assumptions regarding current and the relationship between the emfs and resistances. Some participants express uncertainty about the implications of reversing the polarity of one battery.

Discussion Status

The conversation is ongoing with various interpretations being explored. Some participants have provided guidance on how to approach the problem, while others are questioning the definitions and assumptions made in the calculations. There is no explicit consensus on the correct approach yet.

Contextual Notes

Participants are navigating the constraints of the problem, including the lack of specific current values and the implications of the circuit configuration on the potential difference. There is also a discussion about the expected direction of Vab based on different interpretations of the circuit analysis.

sky.flower1234
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Homework Statement



Find potential difference Vab between points a and b on the figure. All resistances and emf’s are indicated, note the polarity of the batteries. What happens if the polarity of E1 is reversed (polarity of E2 kept the same) and both emfs are made equal?

Homework Equations



Okay, so you definitely need to use Kirchoff's rules here.

I also read in my text that if you want to find Vab all you do is go from point b to point a on your circuit (I'm wondering if me solution is too simple) (I did make a circuit through a program however that proves my answer.

The Attempt at a Solution



For the first part I got that Vab= -(R2(I1+I2)) (I1 and I2 come from E1 and E2)

also, I saw that with switching E2 there is no current through R2. I am not sure why this is true though, is it because a path goes through the least resistance?
 

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So I calculated the total resistance for both emf to be 2R1+2R2, does this sound about right?

I just figured that R2 was in series for both while the 2R1 on the top was in parallel with the 2R1 on the bottom?
 
Hi sky.flower123! :smile:Let's start with the first part of your question.

Shouldn't the currents be eliminated, since they are not given?
I would assume the problem asks for Vab in terms of E1, E2, R1, and R2.Btw, hat do you mean by "total resistance"?
I think you can only talk about a "total resistance" if there is a maximum of 1 emf involved.
And anyway, the problem doesn't ask for a total resistance, does it?As for the second part of your question.
If the emf's are made equal, what would happen to the ratio of the currents?
 
Hey!

When I say total resistance I mean of all the resistance combined in the circuit to help me find I1+I2 (this is including both E1 and E2)

I changed up my formula to say this:

-(R2*(E1+E2/2R1+2R2)

for the second part of the question I guess the ration of my currents would be -1:1? This means they would cancel out?
 
Hmm... that looks...

Right for all parts! :smile:

(Although I would expect the direction of Vab to be the other way around, but if your book says so, then I guess it's okay.)
 
I was mainly just going off of how my book says to go from point B to point A and that Vab=Va-Vb. Plus using Kirchoff's rules I figured that I am going in the way of the current across a resistor so then my change in potential would be negative?
 
You're quite right.
I just expected: Vab = Vb - Va.
But as I said, if your book says it's the other way around, that's what it is for you! :)
 

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