# Circuits and parallel

1. Feb 5, 2008

### buckeyes

Determine the power dissipated in the 8.0 resistor in the circuit shown in the drawing. (R1 = 3.0 , R2 = 8.0 and V1 = 10 V.)

in the picture a 3 ohm resistor is connected in circuit and resistors 2ohms, 1ohm, 1ohm, and 8ohms are all connected in parallel to each other. all are connected to a 10v battery ( i think i attached the picture )

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2. Feb 5, 2008

### buckeyes

ok here is what i tried...
i found the total I to be .381 i did that by adding 1/2+1/1+1/1+1/8=1/2.625=.381
next, i found the voltage after the 3ohm resistor. i did that by V=IR (.381)(3ohms)=1.143
then i found the current at the 8ohm resistor. I=v/r (10/3)=3.3
then, since the voltage across the parallel is the same i found the power at the 8ohm resistor P=VI (1.143)(3.3)=3.81
but that is wrong. where did i mess up?

3. Feb 5, 2008

### TVP45

Do all series equivalents.
Then do all parallel equivalents.
If, as an intermediate step, you wind up two in series, do that equivalent as soon as you can.

4. Feb 5, 2008

### buckeyes

so i add up 3 2 and 1 then 8 and 1 and get two resistors in parallel (6 and 9 ohms). then do i use the same equations as i did before?

5. Feb 5, 2008

### TVP45

No, I should been more specific and said simple series. The 3 Ohm is in series with the network not just the 2 Ohm and 1 Ohm. Try again.

6. Feb 5, 2008

### buckeyes

so would i add up the resistors in parallel so that i ended up with two resistors in circuit first then add the two in circuit?

7. Feb 5, 2008

### TVP45

No. You have a 2 Ohm and a 1 Ohm in simple series. Combine them. What do you get? Are there any others in simple series?

8. Feb 5, 2008

8 and 1?

9. Feb 5, 2008

### TVP45

Yep. So now you have a 1 Ohm and a 2 Ohm combined in simple series. What is their equivalent value?

And, you have a 8 Ohm and a 1 Ohm combined in a simple series. What is their equivalent value.

How are the two equivalents arranged (series or parallel)? How would you combine them?

10. Feb 5, 2008

### buckeyes

3 ohm and 9 ohm connected in parallel. i add them 1/3+1/9=1/.444=2.25ohms. then i would add the other 3 ohm resistor to that giving me 5.25. now i have only one resistor. now i can find total I. right?

11. Feb 6, 2008

### TVP45

You got it. Good work!

12. Oct 2, 2008

### Stryker321

Hey, I am having trouble with this almost identical question. What do you do after you find the total current?

You have to find the current that is traveling through the 8ohm resistor afterward right? How would I do that.

Then to get power it would just be the current traveling through the 8ohm resistor times the (total voltage - voltage of 3ohm reistor)?