P = IV
The Attempt at a Solution
For the first part I solved P = IV for the current flowing through the bulb to find that I = 0.5 A. I then divided 115 Ah by 0.5 A to get 230 hours. Now, I don't really understand what I did here. I just used dimensional analysis to come up with the answer. If anyone can suggest a more mathematical approach or physical approach, that would be nice.
I am not really sure how to get the total energy stored in the battery before it is connected. This number is independent of the light bulb yes? My professor suggested that it was not, but I may have confused what he said.
I know that battery offers a potential of V(t) = 12 volts and a total charge of qtot = (115*3600) C.
I am not sure where to go with this information?