Circular loop problem: finding the radius of a small circle

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Homework Help Overview

The problem involves a pilot executing a circular loop at the speed of sound, with a focus on determining the radius of the smallest circle that can be used without exceeding a specified acceleration threshold. The context includes concepts from circular motion and gravitational forces.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss various equations related to circular motion and question the relevance of gravitational constants in the context of the problem. Some suggest that the acceleration provided can be used directly to find the radius without needing additional constants.

Discussion Status

There is an ongoing exploration of different approaches to the problem, with some participants expressing confusion about the necessity of certain variables. Guidance has been offered regarding the use of acceleration in calculations, and there is a suggestion to simplify the problem by focusing on the relationship between acceleration, velocity, and radius.

Contextual Notes

Participants note the importance of considering the effects of gravity and the potential need to adjust for additional forces acting on the pilot during the loop. There is also mention of the assumptions regarding the constancy of acceleration.

Benzoate
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Homework Statement



In an air show, a pilot is to execute a circular loop at the speed of sound(340 m/s) . The pilot may black out if his acceleration exceeds 8g. Find the radius of the smallest circle he can use. [Take g=10 m s^-2

Homework Equations



possible equations: u^2 >= 2*M*G/a
m*dv/dt=-m*M*G/r^2
m*v^2/r=-m*M*G/r^2

The Attempt at a Solution



u=340 m/s
a=dv/dt=>=80 m s^-2
M=6.00e24 kg
G=6.67e-11

acceleration=dv/dt=> dv/dt=-M*G/r^2

option one
r=sqrt(M*G/(dv/dt)=7.07e12 meters
option 2
a=2*M*G/u^2, a being minimal radius and not the acceleration

a= 28284271.25 meters

actual answer: r>=1445 meters

what did I do wrong? should I have used polar coordinates since the problem states that the plane is going around a loop?

Perhaps I should write:

m*dv/dt=F(z) , F(z) representing the sum of all forces. the only two forces acting on the object is the gravitational force and the centripetal force ; so my equation looks like:

m*dv/dt=m*v^2/r-m*g

dv/dt=dv/dr*dr/dt=dv/dr*v. Now I can integrate in terms of the velocity vector and radius vector.

dv/dr=v^2/r-g

I get something that looks like this:

dv/v=dr/r-dr/g ==> ln v = In r -r/g
 
Last edited:
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Hi,

What equations do you know of that deal with circular motion?

FYI, the "r" in m*M*G/r^2 is not necessarily a radius, it's the distance between two masses.
 
Redbelly98 said:
Hi,

What equations do you know of that deal with circular motion?
hi,

the equations that deal with circular motion are : F(centripetal)=m*v^2/r and the equation for a particle in general motion:
FYI, the "r" in m*M*G/r^2 is not necessarily a radius, it's the distance between two masses.

Well, since the airplane is obviously flying around a circle on earth, then doesn't the radius of the Earth , plus the height the airplane is some distance above the surface of the Earth become relevant in finding the total R=R(earth)+height?
 
Benzoate said:
In an air show, a pilot is to execute a circular loop at the speed of sound(340 m/s) . The pilot may black out if his acceleration exceeds 8g. Find the radius of the smallest circle he can use. [Take g=10 m s^-2

M=6.00e24 kg
G=6.67e-11

Hi Benzoate! :smile:

I'm really confused :confused:

the question gives you the acceleration (8g) … which you can assume is constant (they're telling you g = 10, which is about 2% out anyway :wink:)

you don't need G or M!

Try again (and don't forget you'll have to add or subtract up to 1g for the gravity) :smile:
 
tiny-tim said:
Hi Benzoate! :smile:

I'm really confused :confused:

the question gives you the acceleration (8g) … which you can assume is constant (they're telling you g = 10, which is about 2% out anyway :wink:)

you don't need G or M!

Try again (and don't forget you'll have to add or subtract up to 1g for the gravity) :smile:

could I just write:

a=v^2/r and since I know v and a I can easily calculate r correct?
 
Benzoate said:
could I just write:

a=v^2/r and since I know v and a I can easily calculate r correct?

:biggrin: Woohoo! :biggrin:
 

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