- #1

chwala

Gold Member

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- Homework Statement
- See attached.

- Relevant Equations
- Rate of change

I was able to solve it using,

##\dfrac{dV}{dt} = \dfrac{dV}{dh}⋅\dfrac{dh}{dt}##

With, ##r = \dfrac{h\sqrt{3}}{3}##, we shall have

##\dfrac{dV}{dh} = \dfrac{πh^2}{3}##

Then,

##\dfrac{dh}{dt}= \dfrac{2×3 ×10^{-5}}{π×0.05^2}= 0.00764##m/s

My question is can one use the ##\dfrac{dV}{dt} = \dfrac{dV}{dr}⋅\dfrac{dr}{dt}## approach?

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