Circular Motion -> amusement park ride

In summary, the problem involves finding the number of revolutions per minute a gravitron amusement park ride must execute given a 15m cylinder with a coefficient of static friction of 0.8. Using free body diagrams and equations for friction and centripetal force, the equation v = sqrt(gr/mu) can be used to solve for the necessary revolutions per minute.
  • #1
the_EVIL
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Circular Motion --> amusement park ride

Homework Statement


A gravitron ride at a fair consists of a large 15m cylinder, which rotates about a vertically oriented axis of symmetry. The rider is held to the inner cylinder wall by static friction as the bottom of the cylinder is lowered. If the coefficient of static friction between the rider and the wall is 0.8, then how many revolutions per minute must the cylinder execute?


Homework Equations


Fc= m vsquared/r
Fg= mg


The Attempt at a Solution


I don't really know where to start on this one. all i know is that i have to set up an equivalency, and that mass will somehow end up canceling out. Please help me out here, it would be greatly appreciated! Thanks in advance!
 
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  • #2


You should always start with a free-body diagram with all the forces on it.
Here's a free body diagram (sorry about the suck-ish quality)
http://img198.imageshack.us/img198/6157/freebody.png

You've basically got all the forces, you're just missing the friction equation, which would be
[tex] F_{f} = \mu N[/tex]

So you'd set your equations like this:
[tex] \stackrel{+}{\rightarrow}\Sigma F_{x} = 0 \Rightarrow N - F_c = 0 \Rightarrow N - \frac {mv^2}{r} = 0 \Rightarrow N=\frac {mv^2}{r}[/tex]
[tex] \stackrel{+}{\uparrow}\Sigma F_{y} = 0 \Rightarrow F_{f} - F_{g} = 0 \Rightarrow \mu N - mg = 0 \Rightarrow \mu N = mg [/tex]

Now solve the two equations, substituting N into the second equation
[tex]\mu \frac {mv^2}{r} = mg \Rightarrow v = \sqrt{\frac {gr}{\mu}}[/tex]

And so now you've got "v". The rest shouldn't be hard, try it first.
 
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  • #3


Thanks for the reply! I guess that problem wasn't all that bad at all!
 
  • #4


No prob. Just remember to start with free body diagrams with each physics equation, they're pretty much a must.
 

1. What is circular motion in the context of amusement park rides?

Circular motion is the movement of an object along a circular path, with a constant speed and changing direction. In the context of amusement park rides, this refers to the circular path and changing direction of the ride as it rotates around a central axis.

2. How does circular motion create the feeling of weightlessness on amusement park rides?

Circular motion creates the feeling of weightlessness by exerting centrifugal force on the riders. This force pushes the riders outward and counteracts the force of gravity, making them feel as if they are floating or weightless.

3. What is the relationship between the radius of the ride and the speed of circular motion?

The radius of the ride and the speed of circular motion are inversely proportional. This means that as the radius decreases, the speed of the ride must increase in order to maintain a constant centrifugal force on the riders.

4. Are there any safety considerations for circular motion rides?

Yes, there are several safety considerations for circular motion rides. The ride must be designed and operated within certain speed and radius limits to prevent excessive forces on the riders. In addition, proper restraints and structural integrity of the ride are crucial for ensuring the safety of riders.

5. How do engineers design and test circular motion rides?

Engineers use various mathematical equations and computer simulations to design and test circular motion rides. They also conduct physical tests using scaled-down models or prototypes to ensure the safety and functionality of the ride before it is open to the public.

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