Circular Motion and acceleration

[aznclem]

Ok, for the circular motion, where we are suppose to have 0 acceleration,
this is the problem i have

My question ask for mass of the washers and paper clips by equating Fc to Fg,

and I am given the # of washers,
The radius
and the mass of the stopper.

and the period

now it ask me for mass


how do i find this?
i kno that
Fc = mv^2/r
or
Fc = 4pi^2rm/T^2
and
Fg = mg,
but how do i do it?
i can't seem to figure it out,
even after i figure out the speed, it doesn't help, i have 2 unknowns...The
Fc, and the mass...
help please?


Incase this helps, i am swinging the tubber sopper, with a tube, and below the tube is the paper clip to keep my distance so i kno i am swinging at a constant speed, then at the end of string is my washers for the mass.

 

[Doc Al]

Ok, for the circular motion, where we are suppose to have 0 acceleration,

The centripetal acceleration is certainly not zero!

this is the problem i have

My question ask for mass of the washers and paper clips by equating Fc to Fg,

OK.

and I am given the # of washers,
The radius
and the mass of the stopper.

and the period

now it ask me for mass

So you are given the mass of the stopper and you must compute the mass of the washers?

how do i find this?
i kno that
Fc = mv^2/r
or
Fc = 4pi^2rm/T^2

What mass does m stand for here?

and
Fg = mg,

What mass does m stand for here?

Realize that those equations use different masses: one uses the known mass of the stopper; the other uses the unknown mass of the washers.

 

[m2003]

I understand your confusion and am happy to help. First, let's review the concept of circular motion and acceleration. In circular motion, an object moves along a circular path at a constant speed, but its direction is constantly changing. This change in direction is what we call acceleration. In order for an object to maintain circular motion, there must be a force acting towards the center of the circle, known as centripetal force (Fc). This force is equal to the mass (m) of the object multiplied by its velocity squared (v^2) and divided by the radius (r) of the circle. So, the equation is Fc = mv^2/r.

Now, in your problem, you are given the number of washers, the radius, the mass of the stopper, and the period (T) of the motion. To find the mass of the washers and paper clip, you will need to use both the equations Fc = mv^2/r and Fg = mg. Fg represents the force of gravity, which is equal to the mass (m) of the object multiplied by the acceleration due to gravity (g). In this case, the object is the washers and paper clip, and the acceleration due to gravity is a constant value of 9.8 m/s^2.

To solve for the mass, you will need to set the two equations equal to each other and rearrange to solve for m. The equation will look like this: mv^2/r = mg. You already know the values for v, r, and g, so you can substitute those in and solve for m. Once you have the mass, you can then use it to find the individual masses of the washers and paper clip by dividing by the total number of washers and adding it to the mass of the stopper.

I also wanted to address your concern about having two unknowns in the equation. This is a common issue in physics problems and can be solved by using multiple equations and solving simultaneously. In this case, you have two equations (Fc = mv^2/r and Fg = mg) and two unknowns (m and v). By setting the equations equal to each other, you can eliminate one of the unknowns and solve for the other.

I hope this helps you understand and solve the problem. Remember, when facing a complex physics problem, it's important to break it down into smaller parts