(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

"A 1500kg car rounds a curve of radius 75m at a speed of 25m/s. The curve is banked at an angle of 22 degrees to the horizontal. Calculate:

a) The magnitude of the frictional force.

b) The Coefficient of Kinetic Friction."

2. Relevant equations

F=mv[tex]^{2}[/tex]/r

Answers given:

a) 61000N

b) 0.33

3. The attempt at a solution

What makes sense to me is that the centripetal force is countered by another force. I believe this other force is a combination of the horizontal frictional force & the horizontal normal force (cause from the banked curve resisting the centripetal force).

The centripetal force = 12500N

So,

12500N = Force Frictionx+ Force Normalx= Force Frictionx+ Force Normal*Sin[tex]\phi[/tex]

Force Normal = mg/cos[tex]\phi[/tex]

This however have been unable to get me the provided answers :S.

It seems like a pretty simple question and I have been playing around with it for a bit and keep ending up with 6560N for the frictional force :(.

If anyone could help it would be great...I'm studying for exams! :P

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# Homework Help: Circular Motion and Friction of car turning corner

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