jklops686
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Circular Motion and Static Friction Problem.. "The Wall of Death" ride
A fairground ride called "The Wall of Death" consists of a cylindrical
container of internal diameter 6.50m, mounted on a cylindrical axis.
The passengers feel as if they are being pushed against the wall as the container
begins to rotate. Eventually, the floor is lowered, leaving the miserable passengers
pinned to the wall, apparently defying gravity. When the ride slows down, the
passengers just begin to slide down the wall when they are rotating at 0.400
revolutions per second. Calculate the coefficient of static friction between the wall
and the passengers' backs.
max static friction=coefficient*normal force?
v= 2pi*r/T
I calculated how long it takes to go around in one second (period T) .4x=1 So, 1 rev=2.5 seconds. Now that I have T I also calculated the tangential velocity using the equation above and got 8.17m/s. I think the friction force would be set up as v-f=0 (used free body diagram...tangential velocity and friction cancel out to equal zero?) Which would mean force of friction is 8.17 too. I'm not sure if this is correct, but anyways, i don't know how to find the coefficient of static friction. I would think you would need to know the mass of the person.
Homework Statement
A fairground ride called "The Wall of Death" consists of a cylindrical
container of internal diameter 6.50m, mounted on a cylindrical axis.
The passengers feel as if they are being pushed against the wall as the container
begins to rotate. Eventually, the floor is lowered, leaving the miserable passengers
pinned to the wall, apparently defying gravity. When the ride slows down, the
passengers just begin to slide down the wall when they are rotating at 0.400
revolutions per second. Calculate the coefficient of static friction between the wall
and the passengers' backs.
Homework Equations
max static friction=coefficient*normal force?
v= 2pi*r/T
The Attempt at a Solution
I calculated how long it takes to go around in one second (period T) .4x=1 So, 1 rev=2.5 seconds. Now that I have T I also calculated the tangential velocity using the equation above and got 8.17m/s. I think the friction force would be set up as v-f=0 (used free body diagram...tangential velocity and friction cancel out to equal zero?) Which would mean force of friction is 8.17 too. I'm not sure if this is correct, but anyways, i don't know how to find the coefficient of static friction. I would think you would need to know the mass of the person.
