Circular Motion and static friction

Click For Summary
SUMMARY

The discussion focuses on the application of static friction in circular motion, specifically analyzing a 1050-kg car navigating a turn with a radius of 77 m and a static friction coefficient of 0.80. It concludes that static friction provides the necessary centripetal force to keep the car on its path. Additionally, it examines a 2.00 kg bucket in vertical circular motion, clarifying the forces at play, particularly the tension in the rope and gravitational force, to determine the speed required at both the lowest and highest points of the circle.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of centripetal force and its calculation
  • Familiarity with static friction and its role in circular motion
  • Basic principles of forces acting on objects in vertical circular motion
NEXT STEPS
  • Calculate maximum speed using the formula for centripetal force in relation to static friction
  • Explore the relationship between tension and gravitational force in vertical circular motion
  • Investigate the conditions under which a rope can go slack in circular motion
  • Study the effects of varying the radius and mass on centripetal acceleration
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of circular motion and the forces involved in maintaining motion along curved paths.

MIA6
Messages
231
Reaction score
0
1. What is the maximum speed with which a 1050-kg car can round a turn of radius 77 m on a flat road if the coefficient of static friction between tires and road is 0.80? What does the static friction have to do with this problem? Is the centripetal force equal to this friction? WHy?
2. A bucket of mass 2.00kg is whirled in a vertical circle of radius 1.10 m. At the lowest point of its motion the tension in the rope supporting the bucket is 25.0 N. a) Find the speed of the bucket. b) How fast must the bucket move at the top of the circle so that the rope does not go slack? for a), I got Fcp=Ft-Fg, ('t' means tension) but someone said it was Fcp=Ft+Fg. But tension and the gravity acts in opposite direction at the lower point?! for b), someone said Ft=0? why?

Thanks.
 
Physics news on Phys.org
MIA6 said:
What does the static friction have to do with this problem? Is the centripetal force equal to this friction? WHy?

Yes it is. What other forces could possibly be the centripetal force besides friction? Think of it this way. The car wants to slide out of the curve and move off tangent to it. Static friction holds the car "in place" in that direction. (i.e. at the same radius from the center)

2. A bucket of mass 2.00kg is whirled in a vertical circle of radius 1.10 m. At the lowest point of its motion the tension in the rope supporting the bucket is 25.0 N. a) Find the speed of the bucket. b) How fast must the bucket move at the top of the circle so that the rope does not go slack? for a), I got Fcp=Ft-Fg, ('t' means tension) but someone said it was Fcp=Ft+Fg. But tension and the gravity acts in opposite direction at the lower point?! for b), someone said Ft=0? why?

For part a you are right that Fcp=Ft-Fg. For part b, what will be the the acceleration for which the bucket just makes it around the loop? If you know this, you should be able to find the net force on the bucket, and find the speed of the bucket.
 
G01 said:
For part b, what will be the the acceleration for which the bucket just makes it around the loop? If you know this, you should be able to find the net force on the bucket, and find the speed of the bucket.

If the bucket has no tension, but only gravity, can it still make a vertical circle? Will it fall down? OH, I think it will not because it still has the net force, or centripetal force.
 
Last edited:

Similar threads

Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
20K
  • · Replies 3 ·
Replies
3
Views
7K