1. The problem statement, all variables and given/known data A string is tied to a 4.4 kg block and 120g hanging bucket. Students add 20g washers one at a time to the bucket. The student are unaware that the coefficient of static friction for the block on the table is 0.42. A) what is the maximum force of static friction for the block? B) how many washers can the students add to the bucket without moving the block? 2. The attempt at a solution a)Fs=μsFn = (0.42)(4.4x9.8) Fs= 18.1N b) Ft-Fs=ma Ft-18.1=4.4a Ft=4.4a+18.1 Ft=1.6N Ft-Fg=m(-a) 4.4a+18.1=1.176=0.12a 4.52a=16.924 a=3.74m/s/s I don't know what the next step after this would be. Right now I know that the hanging mass has a tension of 1.6N so another 16.5N can be added to the tension force to reach the maximum static force. I also tried this: Fg=mg 16.5=(0.12+0.02x)(9.8) 16.5=1.176+0.196x 15.324=0.196x x=78 washers The correct answer is 86 washers, but I don't know how to get to this answer.