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## Homework Statement

"A 40 kg child sitting 6.0 m from the center of a merry-go-round has a constant speed of 6.0 m/s. The net work (in Joules) done on the child after making one complete circle on the merry-go-round is?"

## Homework Equations

a=V^2/r

F=ma

C=2pi*r

## The Attempt at a Solution

C ≈ 37.7 m

a = 6 m/s

F at a point = (40)(6) = 240 N

Net work ≈ (240)(37.7) ≈ 9048 J

My question is, is the net work actually 0 J after one full rotation on the merry-go-round, since force is a vector quantity, and the force in one-half of the circular motion negates the force in the other half for each point?

Thanks in advance!