Circular Motion of a car on a track

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SUMMARY

The net force acting on a 1500 kg car driving at 25 m/s around a 200-meter diameter circular track is calculated using the formula F_c = mv²/r, resulting in a net force of 9375 N directed towards the center of the circular path. This centripetal force is primarily provided by the static frictional force between the car's tires and the track surface. Understanding these dynamics is crucial for analyzing circular motion in physics.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with centripetal force concepts
  • Knowledge of static friction and its role in motion
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation and application of the centripetal force formula F_c = mv²/r
  • Explore the role of static friction in maintaining circular motion
  • Learn about the effects of varying speed and radius on net force in circular motion
  • Investigate real-world applications of circular motion in automotive engineering
USEFUL FOR

This discussion is beneficial for physics students, automotive engineers, and anyone interested in the principles of circular motion and forces acting on vehicles in motion.

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[SOLVED] Circular Motion

Homework Statement



A 1500 kg car drives around a flat 200-m-diameter circular track at 25 m/s. What is the magnitude and direction of the net force on the car? What causes this force?

Homework Equations



[tex]F_c = \frac{mv^{2}}{r}[/tex]

The Attempt at a Solution



So I suppose the net force is the force that maintains the circular motion. Thus,

[tex]F_{net} = \frac{(1500)(25)^{2}}{100} = 9375 N[/tex]

However, how exactly would I get the direction of [itex]F_{net}[/itex]? Is it enough to say say towards the center?

And was the cause of the net force the static frictional force of the car?

Thanks in advance!
 
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