- #1
jonasK
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[SOLVED] Circular Motion
A 1500 kg car drives around a flat 200-m-diameter circular track at 25 m/s. What is the magnitude and direction of the net force on the car? What causes this force?
[tex]F_c = \frac{mv^{2}}{r}[/tex]
So I suppose the net force is the force that maintains the circular motion. Thus,
[tex]F_{net} = \frac{(1500)(25)^{2}}{100} = 9375 N[/tex]
However, how exactly would I get the direction of [itex]F_{net}[/itex]? Is it enough to say say towards the center?
And was the cause of the net force the static frictional force of the car?
Thanks in advance!
Homework Statement
A 1500 kg car drives around a flat 200-m-diameter circular track at 25 m/s. What is the magnitude and direction of the net force on the car? What causes this force?
Homework Equations
[tex]F_c = \frac{mv^{2}}{r}[/tex]
The Attempt at a Solution
So I suppose the net force is the force that maintains the circular motion. Thus,
[tex]F_{net} = \frac{(1500)(25)^{2}}{100} = 9375 N[/tex]
However, how exactly would I get the direction of [itex]F_{net}[/itex]? Is it enough to say say towards the center?
And was the cause of the net force the static frictional force of the car?
Thanks in advance!