Circular Motion of amusement park ride

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SUMMARY

The discussion focuses on calculating the speed of seats on a rotating amusement park ride with a circular platform of 7.81 meters in diameter and 10 kg seats suspended by 3.03-meter massless chains. The chains make an angle of 26.1 degrees with the vertical, and gravitational acceleration is 9.8 m/s². The solution involves applying the equations of motion, specifically F=ma and centripetal acceleration (v²/r), to derive the necessary values. The user successfully solved the problem by determining the tension in the chains and the radius of the circular motion.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula v²/r
  • Knowledge of free body diagrams and force analysis
  • Familiarity with trigonometric functions, particularly sine and cosine
  • Basic grasp of Newton's second law, F=ma
NEXT STEPS
  • Study the derivation of centripetal acceleration in circular motion
  • Learn how to construct and analyze free body diagrams for complex systems
  • Explore the application of trigonometric functions in physics problems
  • Investigate the effects of varying angles on tension and speed in circular motion
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Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for practical examples of force analysis in rotational systems.

rg67
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Homework Statement


An amusement park ride consists of a rotating circular platform 7.81m in diameter from which 10kg seats are suspended at the end of 3.03m massless chains. when the system rotates, the chains make an angle of 26.1 with the vertical. Gravity = 9.8m/s^2. what is the speed of each seat? answer in units of m/s.


Homework Equations


F=ma
acceleration centripetal = v^2/r

The Attempt at a Solution


Well i drew a free body diagram and the forces of on the y-axis are Tcos26.1=mg. the forces on the x-axis are (Tsin26.1)r/m=V^2
 
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rg67 said:
Well i drew a free body diagram and the forces of on the y-axis are Tcos26.1=mg.

Good. So T = ____ ?

the forces on the x-axis are (Tsin26.1)r/m=V^2

If you figure out what r is, and use T from the previous equation, you'll have it solved.
 
thanks i solved it
 

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