How Do You Find Velocity in a Rotating Amusement Park Ride?

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SUMMARY

The discussion focuses on calculating the velocity of a seat on a rotating amusement park ride with a circular platform of 8.26 m diameter and 3.9 m massless chains. The chains form an angle of 17.9 degrees with the vertical while the system rotates, and the gravitational acceleration is 9.8 m/s². To find the velocity, participants emphasize the importance of creating a free-body diagram for the seat to analyze the forces acting on it, which is crucial for applying the correct physics principles.

PREREQUISITES
  • Understanding of circular motion and centripetal force
  • Knowledge of free-body diagrams in physics
  • Familiarity with trigonometric functions, specifically tangent
  • Basic grasp of gravitational acceleration and its effects
NEXT STEPS
  • Study the principles of circular motion and centripetal acceleration
  • Learn how to construct and analyze free-body diagrams
  • Explore the relationship between angle, radius, and velocity in rotating systems
  • Investigate the application of trigonometric functions in physics problems
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Physics students, educators, and anyone interested in understanding the dynamics of rotating systems, particularly in amusement park ride design and analysis.

user2867
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Here's the problem. I don't understand how to get the velocity?

If you cannot read the attachment it reads:
An amusement park ride consists of a rotating
circular platform 8.26 m in diameter from
which 10 kg seats are suspended at the end
of 3.9 m massless chains. When the system
rotates, the chains make an angle of 17.9 with
the vertical.
The acceleration of gravity is 9.8 m/s2 .


I tried finding vx then doing vx*tanθ, but the computer said I was wrong...ANY HELP WOULD BE AMAZING! :frown:
 

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You need to do a free-body diagram for the seat.
 

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