Circular motion of stone and rope

[jasonbans]

1. a 2.00-kg stone attached to a rope 4m long is whirled in a circle horizontally on a frictionaless surface, completing 5 revolutions in 2s. calculate the magnitude of tension in the rope



2. delta t = 2pie root square l cost theta/g or f= 1/2pie root square g/ l cos theta



3. is the a conical pendulum question?

 

[PhanthomJay]

The stone is on a frictionless surface on a horizontal table, so this is not a conical pendulum problem. There is only one force acting on it in the horizontal (centripetal)direction. What is the stone's speed and centripetal acceleration?

 

[jasonbans]

apparently there is no speed or centripetal acceleration

 

[PhanthomJay]

The stone is being whirled, so it must have a speed. It is given that its angular speed is 2.5 revolutions per second. You can convert that to an angular speed in radians per second, or a linear tangential speed in meters per second, and solve for the centripetal acceleration using what formula for centripetal acceleration?

 

[jasonbans]

mv^2/r

 

[jasonbans]

The stone is being whirled, so it must have a speed. It is given that its angular speed is 2.5 revolutions per second. You can convert that to an angular speed in radians per second, or a linear tangential speed in meters per second, and solve for the centripetal acceleration using what formula for centripetal acceleration?

lol seriously there is no speed

 

[PhanthomJay]

That's the formula for centripetal force : Fc =mv^2/r, where r and m are given, so you need to find v, the tangential speed of the stone.