Circular Motion, only radius known

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SUMMARY

The discussion revolves around calculating the speed of cars on a carnival ride with a horizontal steel disc of radius 5.0 m and chains of 6.0 m length, where the chains form a 20-degree angle with the vertical. The horizontal radius is determined to be 7.05 m using trigonometric functions. Key equations used include centripetal acceleration (a=mv²/r) and the relationship between speed and period (v=2πr/T). Participants emphasize the importance of understanding the forces acting on the cars, specifically tension and weight.

PREREQUISITES
  • Understanding of circular motion principles
  • Familiarity with trigonometric functions, specifically sine
  • Knowledge of centripetal acceleration
  • Basic physics concepts regarding forces (tension and weight)
NEXT STEPS
  • Study the derivation of centripetal acceleration formulas
  • Learn about the dynamics of tension in non-rigid bodies
  • Explore the application of trigonometry in physics problems
  • Investigate the relationship between angular velocity and linear speed
USEFUL FOR

Students studying physics, particularly those focusing on circular motion and forces, as well as educators seeking to enhance their teaching of these concepts.

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Homework Statement


A carnival ride has a large horizontal steel disc of radius 5.0 m from which cars are suspended by
6.0 m long chains. The disc is rotated about its axis so that the cars swing out and revolve in a
circular path. At its operating speed, the angle of the chains to the vertical is 20 degrees. Find the speed of the cars.


Homework Equations


a=mv^2/r

v=2*pi*r/T


The Attempt at a Solution


Ive started by treating it as a horizontal situation, and found the horizontal radius which equals 6*sin(20) + 5=7.05m. And now I am clueless, where do i go on from here?
Thanks.
 
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Last edited by a moderator:
thank you!

especially that last bit about the chain, never knew that! :biggrin:
 

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