Circular motion problem no idea what's going wrong ><

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irNewton
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Homework Statement



A highway curve of radius 560m is designed for traffic moving at a speed of 73.0km/hr (1216m/s). What is the correct banking angle of the road?


Homework Equations



a=v^2/r
F=ma


The Attempt at a Solution



Forces in t direction:
Fnet=Fncos[tex]\vartheta[/tex]-Fg=0
Fn=mg/cos[tex]\vartheta[/tex]=0


Forces in r direciton:

Fnetr=Fnsin[tex]\vartheta[/tex]=mv^2/r
mgsin[tex]\vartheta[/tex]/cos[tex]\vartheta[/tex]=mv^2/r
tan[tex]\vartheta[/tex]=v^2/r*g
[tex]\vartheta[/tex]=tan-1(1216^2/(9.81*560))
[tex]\vartheta[/tex]= 90 degrees?

which is wrong... = (
 
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double check the way you're assigning your forces, is the Fny component which is cancelling vertical gravity the hypotenuse of the triangle? I find it helpful in these cases to rotate the coordinate system so that the x-axis is actually the sloped road. That way your Fn has only 1 component, and you break down gravity into y & x where x points towards the center of the turn.