Circular Movement Homework: Part A Done, Part B Troubles

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Homework Statement



Everything is in the pictures.
I did part A, I have a problem with part B.
10x in advance.

Homework Equations





The Attempt at a Solution

 

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You need to find the tension as a function of angle. (Forget the tension at the top.)

You have the correct equation. Hint: Express v^2 as a function of angle.
 
Doc Al said:
You need to find the tension as a function of angle. (Forget the tension at the top.)

You have the correct equation. Hint: Express v^2 as a function of angle.

I know this equation (in the pic) but I'm doubtful if this what you meant...

Should I use trigo? can I get another tip :smile:?

10x.
 

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The equation I had in mind was: mv^2/r = T + mg cos(theta).

Another hint: What's conserved as the ball continues on its path?
 
Doc Al said:
The equation I had in mind was: mv^2/r = T + mg cos(theta).

Another hint: What's conserved as the ball continues on its path?

Ok, I already wrote that equation at the beginning in the solution part I uploaded and got stuck there.

I got stuck because I don't know the velocity at this point, I mean, the velocity is not constant, right? there is a mgsin(theta) that keep changing it...I think.

The velocity at the top is not the velocity at the bottom, right?

10x.
 
asi123 said:
I got stuck because I don't know the velocity at this point, I mean, the velocity is not constant, right?
The velocity is definitely not constant. Reread my hint in post #4. :wink:

Given the velocity at the top, you should be able to find the velocity at any point as a function of angle.
 
Doc Al said:
The velocity is definitely not constant. Reread my hint in post #4. :wink:

Given the velocity at the top, you should be able to find the velocity at any point as a function of angle.

:confused: I'm totally stuck, should I use trigo, or there is some equation for the velocity that I don't know about...

Oh, maybe u mean to use energy calculation?
 
asi123 said:
Oh, maybe u mean to use energy calculation?
Getting warmer! :smile:
 
Doc Al said:
Getting warmer! :smile:

The potential energy turns into kinetic energy, no?
 
  • #10
You got it. Keep going.
 
  • #11
Ok, I haven't really learned Conservation of energy so I'm not really familiar with it...

I wrote this equation about the energy, is it correct?

And another thing, What about T? it's not a Conservative force, right? Do I just ignore it in the the energy equation?

10x.
 

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  • #12
asi123 said:
Ok, I haven't really learned Conservation of energy so I'm not really familiar with it...

I wrote this equation about the energy, is it correct?
Looks good to me.
And another thing, What about T? it's not a Conservative force, right? Do I just ignore it in the the energy equation?
Excellent question! Ask yourself: Does the tension force do any work on the ball?
 
  • #13
Doc Al said:
Looks good to me.

Excellent question! Ask yourself: Does the tension force do any work on the ball?

Oh, right, it's vertical to his movement.

10x a lot.
 
  • #14
The ball's movement is always perpendicular to the tension, thus the tension does no work on the ball.
 

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