Circulation Around an Airfoil and Starting Vortex

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SUMMARY

This discussion focuses on the application of Kelvin's circulation theorem to analyze the relationship between circulation around an airfoil and the starting vortex. The theorem, expressed as DΓ/Dt=0, indicates that the circulation remains constant along a closed curve. The circulation (Γ) is crucial for calculating lift and is defined as the closed-loop integral of the velocity at the airfoil's surface. As an airplane accelerates, the circulation around the wings changes, necessitating the formation of a starting vortex to maintain the balance dictated by Kelvin's theorem.

PREREQUISITES
  • Understanding of Kelvin's circulation theorem
  • Knowledge of airfoil dynamics and lift generation
  • Familiarity with vortex formation in fluid dynamics
  • Ability to perform closed-loop integrals in vector calculus
NEXT STEPS
  • Study the implications of Kelvin's circulation theorem in fluid dynamics
  • Learn about the Kutta-Joukowski condition and its role in airfoil theory
  • Explore the mathematical derivation of circulation around various airfoil shapes
  • Investigate the effects of starting vortices on aircraft performance during takeoff
USEFUL FOR

Aerospace engineers, fluid dynamicists, and students studying aerodynamics who seek to understand the principles of circulation and vortex dynamics in relation to airfoil performance.

Plasmosis1
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Homework Statement


Using Kelvin’s circulation theorem, find the qualitative and quantitative relation between the circulation around an airfoil and the circulation of the starting vortex.

Homework Equations


Kelvin's circulation theorem: DΓ/Dt=0

The Attempt at a Solution


I don't really know where to begin because I'm not given any information to work with. I don't even know what kind of airfoil or any flow conditions.
 
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The only information I can give you is that to the degree that I understand it, Kevin's theorem basically states that for any given curve the properties of the fluid traveling along that curve will be constant at all points along that curve.

Beyond that, I hope that someone on our forum more knowledgeable on the subject can expand on how that relates to the problem given to you.
 
Plasmosis1 said:

Homework Statement


Using Kelvin’s circulation theorem, find the qualitative and quantitative relation between the circulation around an airfoil and the circulation of the starting vortex.

Homework Equations


Kelvin's circulation theorem: DΓ/Dt=0

The Attempt at a Solution


I don't really know where to begin because I'm not given any information to work with. I don't even know what kind of airfoil or any flow conditions.

With the circulation Γ the lift of an airfoil (or of a spinning cylinder, etc.) can be calculated. It is defined as the closed-loop integral of the velocity at the surface of the airfoil. Due to friction and inertia the fluid is deflected at the airfoil and will leave the surface parallel to its rearward edge (with no separation/Kutta-Joukowski condition). Calculating the circulation of this situation Γ≠0 - that means it is a difference for a particle wheter it flows on the one side or on the side of the airfoil, so what happens is dependent on the chosen way: The velocity field around the airfoil is not nonrotational, so a vortex is created. As Kelvin’s circulation theorem states that dΓ / dt = 0 and with starting (or variable) air flow the circulation around the airfoil will change (let's assume in the time Δt the change of the circulation was +ΔΓ), there also has to be a circulation -ΔΓ to fulfill Kelvin's theorem. That's what happens during the start of an airplane. When it accelerates the circulation around the wings changes and to "compensate" it another vortex rotating in the opposite direction has to be created - the starting vortex. In steady state flying mode the circulation around the wings is supposed to be constant, as no change occurs no "counter-vortices" are generated.

Γ = (closed-loop)∫ v ⋅ dx (around the airfoil surface)

The questions seems to be rather general, so the answer must be quite general too.
 

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