Circumcentre of an equilateral triangle

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SUMMARY

The circumcentre of an equilateral triangle with side length 'a' is located at a distance of a/sqrt(3) from any vertex. This conclusion is derived by analyzing the triangle formed by dropping a perpendicular from the circumcentre to a side, creating a 30-60-90 triangle. The Pythagorean theorem can also be applied to find the circumcircle radius 'r' by relating it to the previously calculated distance a*sqrt(3)/2. Trigonometric functions are not necessary for this calculation.

PREREQUISITES
  • Understanding of equilateral triangles and their properties
  • Knowledge of the Pythagorean theorem
  • Familiarity with 30-60-90 triangles
  • Basic trigonometric concepts (optional)
NEXT STEPS
  • Study the properties of circumcentres in various types of triangles
  • Learn how to apply the Pythagorean theorem in different geometric contexts
  • Explore the derivation of the circumradius formula for equilateral triangles
  • Investigate the relationships between triangle side lengths and angles
USEFUL FOR

Students studying geometry, mathematics educators, and anyone interested in the properties of triangles and their circumcentres.

Chronos000
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1. Homework Statement [

what is the distance from one corner of an equilateral triangle of sides a to the circumcentre?


I can figure out the length from one corner to the opposite side to be sqrt3*a/2 but that's about it. I just can't see how to do this.

thanks
 
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Drop a perpendicular from the circumcenter to a side. That gives you a 30-60-90 triangle whose hypotenuse is the radius you are looking for.
 
thanks, the answer is a/sqrt3, I thought there was some way to do this without cos or sin but perhaps not
 
Chronos000 said:
thanks, the answer is a/sqrt3, I thought there was some way to do this without cos or sin but perhaps not

You could just use the pythagorean theorem if you really want to. If you call the circumcircle radius r, then the a*sqrt(3)/2 distance you computed minus r is the shorter leg of your 30-60-90 triangle. Now use the pythagorean theorem on it to solve for r. You don't really NEED the trig.
 

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