The rule states that:(adsbygoogle = window.adsbygoogle || []).push({});

[itex] { lim }_{ x\rightarrow c }\quad \frac { f(x) }{ g(x) } \quad =\quad { lim }_{ x\rightarrow c }\quad \frac { f'(x) }{ g'(x) } [/itex]

Right?

So if

[itex] { lim }_{ x\rightarrow 2 }\frac { { x }^{ 2 }+1 }{ x-1 } \quad =\quad 5 [/itex]

Then shouldn't

[itex] { lim }_{ x\rightarrow 2 }\frac { { (x }^{ 2 }+1)' }{ (x-1)' } \quad =\quad 5 [/itex]

Also equal to 5? However, it equals to 4. Can someone help me understand why?

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Clarification on L'Hopital's Rule?

Loading...

Similar Threads - Clarification L'Hopital's Rule | Date |
---|---|

I Clarification about Integration | Feb 15, 2017 |

Definition clarification for Fourier transform | Sep 20, 2015 |

Clarification on a topic in Apostol's calculus text | Mar 27, 2015 |

Clarifications regarding definitions of Taylor, Laurent etc. series | Feb 16, 2014 |

**Physics Forums - The Fusion of Science and Community**