- #1
krackers
- 72
- 0
The rule states that:
[itex] { lim }_{ x\rightarrow c }\quad \frac { f(x) }{ g(x) } \quad =\quad { lim }_{ x\rightarrow c }\quad \frac { f'(x) }{ g'(x) } [/itex]
Right?
So if
[itex] { lim }_{ x\rightarrow 2 }\frac { { x }^{ 2 }+1 }{ x-1 } \quad =\quad 5 [/itex]
Then shouldn't
[itex] { lim }_{ x\rightarrow 2 }\frac { { (x }^{ 2 }+1)' }{ (x-1)' } \quad =\quad 5 [/itex]
Also equal to 5? However, it equals to 4. Can someone help me understand why?
[itex] { lim }_{ x\rightarrow c }\quad \frac { f(x) }{ g(x) } \quad =\quad { lim }_{ x\rightarrow c }\quad \frac { f'(x) }{ g'(x) } [/itex]
Right?
So if
[itex] { lim }_{ x\rightarrow 2 }\frac { { x }^{ 2 }+1 }{ x-1 } \quad =\quad 5 [/itex]
Then shouldn't
[itex] { lim }_{ x\rightarrow 2 }\frac { { (x }^{ 2 }+1)' }{ (x-1)' } \quad =\quad 5 [/itex]
Also equal to 5? However, it equals to 4. Can someone help me understand why?