Clausius-Clapeyron equation and water

[genericusrnme]

Homework Statement

Using the Clausius-Clapeyron equation, determine the slope of dp/dT for water-ice I equilibrium and explain why you can skate on ice but not on solid argon.

Homework Equations

Clausius-Clapeyron equation

The Attempt at a Solution

I know what the clausius-clapeyron equation is but I have no idea how I'm supposed to determine the slope for water - there is no information in the book so far on water so I really have no idea how I could write the change in entropy and volume as functions of temperature..

I'm completely at a loss here (and most likely overlooking something simple)

(I wasn't sure if this should be in introductory or advanced physics, the textbook I'm using doesn't really mention what level it's geared at)

 

[TSny]

Consider the melting of 1 gram of H₂O.

Note ΔS= Q/T where Q is the heat required to melt 1 gram of ice (79.7 cal = 333 J) and T is the temperature corresponding to equilibrium between ice and water.

ΔV = V_f-V_i where V_i is the volume of 1 gram of ice and V_f is the volume of 1 gram of water. You can calculate these volumes from the known densities of ice and water at the melting point temperature (ice: 0.917 g/cm³, water: 1.000 g/cm³).

Watch your units.

 

[genericusrnme]

Ah, thank you!
I knew it'd turn out to be something simple