Clay-stick inertia & energy problem

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Homework Help Overview

The problem involves a thin stick and a piece of clay, focusing on the conservation of angular momentum and mechanical energy after a collision. The stick is hinged, and the clay collides with it at a specific distance from the hinge, raising questions about energy ratios before and after the collision.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of angular velocity and the ratio of final to initial mechanical energy. There are questions about rounding errors and the format of the answer. Some participants explore the assumption of mechanical energy conservation in the system of clay and stick.

Discussion Status

The discussion is ongoing, with participants sharing their calculations and questioning the assumptions regarding energy conservation. There is no explicit consensus on the correct approach or answer yet, as different interpretations are being explored.

Contextual Notes

Participants note the lack of an official answer and the potential impact of rounding errors on calculations. The discussion also highlights the assumption of no friction at the pivot and its implications for mechanical energy conservation.

MickeyBlue
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Homework Statement


A thin stick of mass M = 2.8 kg and length L = 2.2 m is hinged at the top. A piece of clay, mass m = 0.8 kg and velocity V = 2.7 m/s hits the stick a distance x = 1.65 m from the hinge and sticks to it.

Q2: What is the ratio of the final mechanical energy to the initial mechanical energy?

Homework Equations


1. Lf = Li (conservation of angular momentum)
2. Is = ⅓ML2
3. Ic = mx2
4. Krot = ½Iω2
5. Kl =½mVt2

The Attempt at a Solution


Clay-stick problem.jpg

I can't find the problem with my working in part 2; wondering if someone can point me in the right direction please. I calculated the angular velocity as 0.53 rad/s.
 
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MickeyBlue said:

Homework Statement


A thin stick of mass M = 2.8 kg and length L = 2.2 m is hinged at the top. A piece of clay, mass m = 0.8 kg and velocity V = 2.7 m/s hits the stick a distance x = 1.65 m from the hinge and sticks to it.

Q2: What is the ratio of the final mechanical energy to the initial mechanical energy?

Homework Equations


1. Lf = Li (conservation of angular momentum)
2. Is = ⅓ML2
3. Ic = mx2
4. Krot = ½Iω2
5. Kl =½mVt2

The Attempt at a Solution


View attachment 106431
I can't find the problem with my working in part 2; wondering if someone can point me in the right direction please. I calculated the angular velocity as 0.53 rad/s.
I get almost the same, but you might have some rounding error. Keep another digit of precision all the way through. I get .325.
I note that it asks for the ratio, so technically the answer should be of the form 0.32:1. Do you know what the official answer is?
 
No, I don't have an official answer yet. I thought the same about the ratio, but my online submission doesn't recognise colons.
 
I'd like to follow up from my previous answer: if the clay and the stick are taken as one system, and we assume no friction about the pivot, is the case not that mechanical energy is conserved? That would make the ratio 1:1 (or just 1).

I'm not 100% sure on this.
 
MickeyBlue said:
I'd like to follow up from my previous answer: if the clay and the stick are taken as one system, and we assume no friction about the pivot, is the case not that mechanical energy is conserved? That would make the ratio 1:1 (or just 1).

I'm not 100% sure on this.
The initial mechanical energy must be that before the collision. Since the bodies coalesce, it cannot be conserved.
 

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