Clear misconception: Angular Momentum of Merry Go Round vs Ice Skater

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SUMMARY

The discussion clarifies the misconception regarding the rotational speeds of horses on a merry-go-round compared to ice skaters. It establishes that conservation of mass is not applicable; instead, conservation of angular momentum is relevant but not in this context since the horses remain at fixed distances from the axis of rotation. The key takeaway is that the linear speed of each horse is determined by its distance from the center, with horses farther from the center traveling a larger circumference in the same time frame, resulting in higher linear speeds.

PREREQUISITES
  • Understanding of angular momentum principles
  • Basic knowledge of rotational motion
  • Familiarity with linear speed and distance relationships
  • Knowledge of circular motion and circumference calculations
NEXT STEPS
  • Study the principles of conservation of angular momentum in rotational systems
  • Learn about the relationship between linear speed and radius in circular motion
  • Explore the physics of rotational motion with examples from real-life scenarios
  • Investigate the mathematical formulas for circumference and their applications in physics
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Students studying physics, educators teaching rotational dynamics, and anyone interested in understanding the mechanics of circular motion and angular momentum.

fignewtons
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Homework Statement


Why is it that the horse closest to the axis of rotation on a merry go round spins slower than the horse on the outer edges of the merry go round?
I saw this video on youtube and got confused at the first merry go round example:


According to conservation of mass, isn't v inversely related to r, so shouldn't the inner horse spin faster? In the same way that ice skaters extend their arms to spin slower and pull in their arms to spin faster?

Please explain, thanks! Feel free to use math, examples, etc.
 
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figNewtons said:

Homework Statement


Why is it that the horse closest to the axis of rotation on a merry go round spins slower than the horse on the outer edges of the merry go round?
I saw this video on youtube and got confused at the first merry go round example:


According to conservation of mass, isn't v inversely related to r, so shouldn't the inner horse spin faster? In the same way that ice skaters extend their arms to spin slower and pull in their arms to spin faster?

Please explain, thanks! Feel free to use math, examples, etc.

Conservation of mass isn't relevant. Perhaps you're thinking of conservation of angular momentum?

Unlike for your figure skater example, no mass is moving inwards or outwards to or from the axis of rotation; the horses are at fixed distances from the center. So conservation of angular momentum doesn't apply (or rather it isn't relevant) to your problem.

What applies is rotational velocity and how the linear (tangential) speed of the horse depends upon its distance from the center of rotation. You should agree that all the horses make a complete circuit in the same amount of time (since they're fixed to a rigid platform which turns at a given rate). But the total distance traveled by each horse differs depending upon the circumference of the circle it follows at its given radial distance. What's the formula for the circumference of a circle? The more distance it covers in the same amount of time, the faster its linear speed.
 

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