1. The problem statement, all variables and given/known data A clock has a 20 cm minute hand. From the 6 PM mark to the 9 PM mark, for the tip of the minute hand, calculate: a. the displacement vector in unit-vector notation. b. the average velocity vector in unit-vector notation. c. the average acceleration vector in unit-vector notation. d. calculate the magnitude and direction of the average acceleration vector. 2. The attempt at a solution a. I named my 6 PM vector B and my 9 PM vector A. A=-20i and B=-20j. A-B=C(the displacement vector) which equals -20i+20j b. V=(-20i+20j)/15min= -4/3i+4/3j cm/min c. Vi=Vf=40∏/60=2∏/3 Vi=-2∏/3i Vf= 2∏/3j Aave= (2∏/3i+2∏/3j)/15min = 2∏/45i+2∏/45j cm/min^2 d. √((2∏/45)^2)+(2∏/45)^2) = .197 cm tanΘ=2∏/45/2∏/45 = 45° I am not sure if I did b, c, or d right.