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A clock has a 20cm minute hand. From the 6PM mark to the 10PM mark, for the tip of the minute hand, calculate:

a) the displacement vector in unit-vector notation

b) the average velocity vector in unit-vector notation

c) the average acceleration vector in unit-vector notation

d) calculate the magnitude and direction of the average acceleration vector

So I have solved for a is -20cos 30i + 30j

and b is (-20cos 30i+30j)/ 1200 seconds I believe

I really don't understand how you would find the avg acceleration for this problem. I know how to find the magnitude just a^2+b^2= c^2, and I'm not exactly sure how the direction is solved, i think it's tan-1 (Vi/Vf)?

So I just need some help and an explanation on C and how to find the direction. Thanks

a) the displacement vector in unit-vector notation

b) the average velocity vector in unit-vector notation

c) the average acceleration vector in unit-vector notation

d) calculate the magnitude and direction of the average acceleration vector

So I have solved for a is -20cos 30i + 30j

and b is (-20cos 30i+30j)/ 1200 seconds I believe

I really don't understand how you would find the avg acceleration for this problem. I know how to find the magnitude just a^2+b^2= c^2, and I'm not exactly sure how the direction is solved, i think it's tan-1 (Vi/Vf)?

So I just need some help and an explanation on C and how to find the direction. Thanks

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