Closed form for geometricish series (index squared in the exponent)?

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SUMMARY

The discussion centers on finding a closed form for the series \(\sum_{k=0}^n x^{k^2}\). It is established that there is no known closed form for the finite sum, while the infinite sum \(\sum_{k=0}^{\infty} x^{k^2}\) can be expressed using the Jacobi theta function as \((\theta(0, x) + 1)/2\) for \(-1 < x < 1\). Participants also explore the need for a lower bound for the modified series \(\sum_{k=0}^n [x^k + x^{k(k+1)/2} - 1]\) as \(n\) approaches infinity, noting that while the series initially increases, it eventually decreases.

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Closed form for "geometricish" series (index squared in the exponent)?

Hi all,

Is there a nice closed form for the following series?

\sum_{k=0}^n x^{k^2}

Even a decently tight upper bound and lower bound would be nice (obviously it is bounded by the corresponding geometric series \sum x^k, but is there anything better?).

Thanks!
 
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Hi !
As far as I know, there is no referenced closed form for the finite sum x^k² , k=0 to n.
The closed form for the infinite sum x^k² k=0 to infinity, with -1<x<1, is =(theta(0 , x)+1)/2 , involving the Jacobi theta function.
 
Thanks for the reply! It turned out that the plain old geometric upper bound was sufficient for what I was doing before, but now I need a lower bound for the following sum for x \in (0,1).

<br /> \sum_{k=0}^n [x^k + x^{k(k+1)/2} - 1]<br />

Clearly as n goes to infinity, this sum goes to negative infinity, but first it will increase with n and then decrease. I want a lower bound that captures that beginning increasing part. I don't really understand much about the Jacobi theta function so I'm not sure if it would be useful here too...

Essentially what I need is a closed form lower bound so that I can solve an inequality for n.
 

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